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7n^2+27n+18=0
a = 7; b = 27; c = +18;
Δ = b2-4ac
Δ = 272-4·7·18
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-15}{2*7}=\frac{-42}{14} =-3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+15}{2*7}=\frac{-12}{14} =-6/7 $
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